Disclaimer
Information OurBlock provides is made available solely to protect the public. Using this information to harass, threaten, or harm anyone is prohibited. Information is provided by third parties and may have errors. We cannot guarantee the accuracy, completeness, or timeliness of the information. Location data may not be 100% accurate. Use extreme care and always verify information through official sources and exercise caution and judgment when using OurBlock. By clicking continue, I agree I have read and understand the above and agree to these terms and conditions.

Injury accident at Parthenia St and Columbus Ave intersectionLos Angeles CA

audio iconTraffic
Columbus Ave & Parthenia St, Los Angeles, CA 91343

An injury accident involving a vehicle occurred at the intersection near Parthenia Street and Columbus Avenue in Los Angeles. Firefighters and police responded, and medical personnel assessed the patient to determine the need for basic life support.

Audio|Source: Los Angeles City Fire
00:58
Transcript:
00:00
207 injury intersection Parthenia and Columbus.
00:08
Venture engine 7, we're out seen here at Parthenia and Columbus with LAPD.
00:12
Is that for the call? You sent 207 on?
00:21
Engine 7, LAP is a separate incident.
00:25
This was going to be an assault.
00:31
Section 3rd 29, Rivers Fire intersection, Burbank, and you're through.
00:37
Metro and we're on scene with LAPD assessing a patient.
00:41
We'll handle and let you know if we need R.A.
00:47
87, Roger.
00:51
That's right.
00:53
We'll take a BLS Rescue, Parthenia and Columbus.
00:56
Same address 15313.

Disclaimer:
This transcript was automatically generated and may contain inaccuracies. Please verify the information independently.

Location mentioned:
Columbus Ave & Parthenia St, Los Angeles, CA 91343

This shows a Google Street View of the area near the location, which might not be the exact address.

Correct
Incorrect

Explore More on Los Angeles, CA Crime Map

Recent Traffic Incidents in Los Angeles, CA

Explore the crime map for more.